solve the simultaneous equations: 2x-3y = 16 and x + 2y = - 6

First we need to subtract a variable from another to eliminate a variable from both equations. To do this we need to make either the X value the same or the Y value the same.We can do this by multiplying the second equation by two giving us 2X + 4Y = -12Now we have a 2x in the first equation and the second.2x - 3y = 162x + 4y = -12 Now subtract the second equation from the first. (take care with the negative values-7y = 28Next divide both sides by -7y= 28/-7 = -4So now we have our y value (-4)Next, substitute the y value into one of the equations.x + 2y = -6x + 2(-4) = -6 Expand out the bracketx - 8 = -6 Add 8 to both sidesx = 2SOLUTION: X = 2 Y = -4

DR
Answered by Dana R. Maths tutor

4369 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the simultaneous equations y=x-5 and 10y=2x+6 by elimination, and by substitution.


how do you work out the gradient and point of interception of a linear graph given some coordinates


A shop sells only Apples, Bananas and Mangos. The ratio of Apples to Bananas is 5:11. The next shopper will choose one piece of fruit at random. The probability that they buy a Mango is 0.2. What is the probability that they buy an Apple?


You are told that the y is proportional to x^2 and that when y=75, x=5. Find a formula for x in terms of y.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning