Paul buys three pens and one pencil for £11 while Sam buys four pens and two pencil for £16 - what is the price of pens and pencils?

Read the question and translate the information into equations.'Three pens and one pencil for £11' can be written as 3x + y = 11 where x = pens and y = pencils. 'Four pens and two pencils for £16' can be written as 4x + 2y = 16. We now have the equations 3x + y = 11 and 4x + 2y = 16. We want to manipulate one of the equations so that we either have the same x value or the same y value as this will let us subtract one equation from the other, meaning we will have an equation in only one variable which can be solved. In this case we can divide both sides of equation 2 by two, so '4x+2y = 16' becomes '2x+y=8'. Then we have 3x + y =11 and 2x + y = 8. At this point we have the same y value in each equation, so we can subtract equation 2 from equation 1: (3x + y) - (2x + y) = 11 - 8 = 3 so 3x - 2x + y - y = 3x = 3. At this point we have solved the equations for x, so we can choose an equation to use this x value to solve y. Using equation one, we have 3x + y = 11. We can substitute our solution x = 3 into this equation so 3(3) + y = 11 so 9 + y = 11 so y = 11 - 9 = 2. So the solution is x = pens = £3 and y = pencils = £2.

IS
Answered by Isabelle S. Maths tutor

2719 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How will you help with my studies?


The length of a rectangle is five times the width. The area of the rectangle is 1620cm2. Work out the width of the rectangle.


What is the hypotenuse of the triangle if the other 2 sides are 8cm and 6cm?


Solve the folllowing quadratic equation: y=x^2+x-6


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning