Solve the simultaneous equation 2x-4y=8 and 3x+3y=-15

Set 2x-4y=8 as equation 1, and 3x+3y=-15 as equation 2. Multiply equation 1 by 3 and equation 2 by 4 so they look like 6x-12y=24 and 12x+12y=-60. Now add the two equations and you get 18x=-36 or x=-2. Substitute this back into equation 2 and you get -6+3y=-15. Add 6 to both sides and you get 3y=-9 or y=-3.

DL
Answered by Daniel L. Maths tutor

3834 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

For all values of x, f(x) = (x + 1)^2 and g(x) = 2(x-1). Show that gf(x) = 2x(x + 2) and find g^-1(7)


Solve the equation x^{2}-2x-15 = 0


What are the external angles of a regular hexagon?


Dividing Fractions


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning