Write the equation x^2 + 6x - 40 = 0 in the form (x + a)^2 - b = 0 and then solve for x

(x2 + 6x + 9) - 49 = 0
(x + 3)2 - 49 = 0

then to solve

(x + 3)2 = 49
x + 3 = +-7
x = -10 or x = 4

DS
Answered by Darragh S. Maths tutor

4166 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

3/(x-1) - 2/(x+1) = 1 Solve to find the values of x.


How do I solve a simultaneous equation like this: 2x-5y=3, 3x+2y=14 ?


solve simultaneous equations: 2x² + 3y² = 14 , x = 2y-3


Expand (x+3)(x+2)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning