Differentiate (2a+3)^5/2 with respect to a
Let u=2a+3, therefore du/da=2. Let y=u^5/2, therefore dy/du=5/2(u)^3/2 Hence dy/da=du/da*dy/du=2(5/2)*u^3/2=5u^3/2
GT
Related Maths GCSE answers
All answers ▸Where do the two lines intersect? (a) 3x+6y= 15 (b) y= 6x -4 (GCSE-Higher Tier)
Show that (x + 1)(x + 2)(x + 3) can be written in the form ax3 + bx2 + cx + d where a, b, c and d are positive integers.
x : y = 7 : 4, x + y =88. Work out the value of x - y.
Simplify 3/(x+1) + (3x-9)/2 = 1, to get a quadratic equation in the format ax^2 + bx + c = 0.