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Part 2: from the empirical formula, calculate the molecular formula if the molecular weight of the substance is 180 g/mol

Molcular weight of CH2O = 30 g/mol 180/30 = 6 Molecular formula = C6H12O6
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Answered by Rachael T. • Chemistry tutor
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Part 1: Calculate the empirical formula for a substance with the following composition: H 6.71%; C 40.00%; O 53.29%

C = 12 g/molO = 16 g/molH = 1 g/mol Ratio of C = 40/12 = 3.33Ratio of O = 53.29/16 = 3.33Ratio of H = 6.71/ 1 = 6.71Divide largest value by smallest value = 6.71/3.33 = 2Empirical formula = CH2O
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Answered by Rachael T. • Chemistry tutor
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Write an equation for the complete combustion of C9H20

Complete combustion is the oxidation of a fuel where the only products exist as CO 2 and H 2 O. C 9 H 20 + nO 2 ==> nCO 2 + nH 2 O C 9 H 20 + 19O 2 ==> 9CO 2 + 10H 2 O use the molecular formula of the ...
HF
Answered by Harry F. • Chemistry tutor
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Why does hydrogen bonding occur in water?

Hydrogen bonding results from the great difference in electronegativity between oxygen and hydrogen. Electronegativity is the ability of an atom to pull electrons towards itself in a covalent bond. As oxygen...
MO
Answered by Myles O. • Chemistry tutor
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What are the redox reactions involving carbonyls?

Carbonyls are aldehydes and ketones, both can be a product of an alcohol's oxidation reaction. A common reagent for that is potassium dichromate and sulphuric acid (the dichromate ion is reduced to a Cr 3+ a...
KJ
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