Part 1: Calculate the empirical formula for a substance with the following composition: H 6.71%; C 40.00%; O 53.29%
C = 12 g/molO = 16 g/molH = 1 g/mol
Ratio of C = 40/12 = 3.33Ratio of O = 53.29/16 = 3.33Ratio of H = 6.71/ 1 = 6.71Divide largest value by smallest value = 6.71/3.33 = 2Empirical formula = CH2O
RT
Related Chemistry A Level answers
All answers ▸What is the difference of SN1 and an SN2 mechanism?
Why do first ionisation energies decrease down a group?
How can I use an infrared spectrum with a mass spectrum to identify an unknown compound?
What are the differences between covalent and ionic bonding?