Part 1: Calculate the empirical formula for a substance with the following composition: H 6.71%; C 40.00%; O 53.29%
C = 12 g/molO = 16 g/molH = 1 g/mol
Ratio of C = 40/12 = 3.33Ratio of O = 53.29/16 = 3.33Ratio of H = 6.71/ 1 = 6.71Divide largest value by smallest value = 6.71/3.33 = 2Empirical formula = CH2O
RT
Related Chemistry A Level answers
All answers ▸Why does an ionic compound (e.g. NaCl) conduct electricity when molten or dissolved in water, but not when it is a solid.
Explain how a coordinate bond forms
Can you help me with the question: "State and explain the trend in boiling temperature of hydrogen halides down the group"?
What is the difference between a nucleophile and an electrophile?