Part 1: Calculate the empirical formula for a substance with the following composition: H 6.71%; C 40.00%; O 53.29%

C = 12 g/molO = 16 g/molH = 1 g/mol
Ratio of C = 40/12 = 3.33Ratio of O = 53.29/16 = 3.33Ratio of H = 6.71/ 1 = 6.71Divide largest value by smallest value = 6.71/3.33 = 2Empirical formula = CH2O

RT
Answered by Rachael T. Chemistry tutor

1979 Views

See similar Chemistry A Level tutors

Related Chemistry A Level answers

All answers ▸

What is meant by the term chiral?


Explain why the boiling point increases from sodium to aluminium.


How do mass spectrometers measure the mass of a compound?


How does ionic bonding work and what is the structure of an ionic compound?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning