Part 1: Calculate the empirical formula for a substance with the following composition: H 6.71%; C 40.00%; O 53.29%
C = 12 g/molO = 16 g/molH = 1 g/mol
Ratio of C = 40/12 = 3.33Ratio of O = 53.29/16 = 3.33Ratio of H = 6.71/ 1 = 6.71Divide largest value by smallest value = 6.71/3.33 = 2Empirical formula = CH2O
RT
Related Chemistry A Level answers
All answers ▸How do I calculate rate coefficient units?
Rank the following acids according to acid strength, strongest to weakest: HF, HCl, HBr. Explain your reasoning.
Why does a catalyst speed up a chemical reaction?
How can you deduce the order of the reaction with respect to the reagent based on the graph of its concentration against time?