Part 1: Calculate the empirical formula for a substance with the following composition: H 6.71%; C 40.00%; O 53.29%
C = 12 g/molO = 16 g/molH = 1 g/mol
Ratio of C = 40/12 = 3.33Ratio of O = 53.29/16 = 3.33Ratio of H = 6.71/ 1 = 6.71Divide largest value by smallest value = 6.71/3.33 = 2Empirical formula = CH2O
RT
Related Chemistry A Level answers
All answers ▸3-methyl pent 2 ene reacts with HBr to form two products. Which of these products is the minor and major product and why?
Pure water has a boiling point of 100 °C and a freezing point of 0 °C. What is the boiling point and freezing point of a sample of aqueous sodium chloride?
What is the difference between an isotopic and isoelectronic species?
Describe the features of a benzene ring that define its reactivity. How does phenol differ from this?