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A curve has the equation y=3 + x^2 -2x^3. Find the two stationary points of this curve.

At stationary point the derivative of y with respect to x equals zero. Find dy/dx. dy/dx = 2x - 6x 2. Set dy/dx = 0 ,giving 2x - 6x 2 = 0. We can rearrange this to x(1-3x) = 0 and solve the equation for x. T...
TC
Answered by Thomas C. Maths tutor
4830 Views

Find the derivative of the following function: f(x) = x(x^3 + 2x)

f(x) becomes f'(x)1) First multiply out the brackets (by adding the indices) = x^4 + 2x^22) Then differentiate this. The indices moves to the front and multiplied by the number before the x. The indices is t...
SS
Answered by Shamailla S. Maths tutor
3483 Views

Express 2 ln(3) + ln(11) as a single natural logarithm

To simplify this equation we need to understand the rules of logarithm equations. When we add two natural logs (ln) together, we must actually multiply the contents of the brackets. For example:ln(5) + ln(9)...
JK
Answered by Jordan K. Maths tutor
10593 Views

Differentiate with respect to x. y(x) = e^(7x^2)

dy/dx = 14xe^(7x^2)
PM
Answered by Pablo M. Maths tutor
3876 Views

integrate( x^3+4x^2+3)dx

=(x^4)/4+(4x^3)/3 + 3x + c
RH
Answered by Rory H. Maths tutor
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