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A ball is released from rest at a height of 4m. At what speed does it hit the ground?

First write out information from the question.s=4m u=0m/s v=? a=9.8m/s 2 t=Choose correct "suvat" equation: v 2 =u 2 +2asSubstitute in known variables.Obtain v= 8.9m/s
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Answered by Molly A. • Maths tutor
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Express (x + 1)/((x^2)*(2x – 1)) in partial fractions

(x + 1)/((x^2)*(2x – 1)) = -3/x - 1/x^2 + 6/(2x-1)
DH
Answered by Douglas H. • Maths tutor
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Integrate 2x^4 - 4/sqrt(x) + 3 dx

First we will simplify 4/sqrt(x) so it is easier to integrate.sqrt(x) is equal to x 1/2 , therefore 4/sqrt(x) = 4/x 1/2 .We bring up x 1/2 so 4/x 1/2 becomes 4x -1/2 .So now we will integrate the simplified ...
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Answered by Maleehah A. • Maths tutor
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Differentiate Y = 4X/(X^2+5) and give dy/dx in its simplest form

4(5-X^2)/(X^2+5)^2
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Answered by Mohamed S. • Maths tutor
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Given that the increase in the volume of a cube is given by dV/dt = t^3 + 5 (cm^3/s). The volume of the cube is initially at 5 cm^3. Find the volume of the cube at time t = 4.

Identify that this is a rate of change question and set up the boundary conditions of V = 5 when t = 02) Take the dt to the right side and explain to integrate both sides of the equation to 'sum over all the...
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Answered by Tommy W. • Maths tutor
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