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A curve has equation y = e^(3x-x^3) . Find the exact values of the coordinates of the stationary points of the curve and determine the nature of these stationary points.

In order to find the stationary points we need to find the first derivative, set it to 0 and solve for x. We can then use this value to find the value for y.y = e (3x-x^3) We know for the derivative of e to ...
PM
Answered by Philip M. Maths tutor
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Find the derivative of x(x+3)^5

First we use the product rule, so we multiply x by the derivative of (x+3) 5 . To find the derivative of (x+3) 5 we use the chain rule. So we have 5(x+3) 4 . So the first part of our product rule calculation...
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Answered by John Y. Maths tutor
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Sketch 20x--x^2-2x^3

Find roots, stationary points, classify, sketch.
TF
Answered by Tom F. Maths tutor
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Find dy/dx when y = (3x-1)^10

First the power will be taken into account: multiply by 10 and take one away from the power: y = 10(3x-1)^9 2) Then we will differentiate what is in the brackets and multiply it by step 1: y = (3x-1)dy/dx = ...
SR
Answered by Sakina R. Maths tutor
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By first expanding the brackets, differentiate the equation: y=(4x^4 + 3x)(2x^2 - 9)

In this case the question has given you a clue as to the order that you solve the question. So, first we need to expand the brackets, multiplying each term by one another to get; y=8x^6 - 36x^4 + 6x^3 - 27x....
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Answered by Patrick A. Maths tutor
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