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x^3-6x^2+9x=x(x^2-6x+9) observe binomial formula (x-3)^2=(x^2-6x+9) Thus x(x-3)^2 and the function has two points meeting the x-axis.

First step: integrate int df/dx = x^2+3x+c (never forget the constant!) Second step: substitute the point in order to get c 1 = (1)^2+3*1+c -> c = 1-1-3=-3 Thus, f = x^2+3x-3

The moment of a force about any point is defined as the force x perpendicular distance from the line of action of the force to the point - moment = F x d the unit is Nm. Principle of moments states that for ...

Scalars have a magnitude (size) only. Vectors have both magnitude and direction.

Since there is an x written as a power here, it suggests that this question should be solved using logs (here assume I am using the natural logarithm, which has base e). Taking logs of both sides of the equa...