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A particle of mass 5kg is held at rests on a slope inclined at 30 degrees to the horizontal. The coefficient of friction for the slope is 0.7, determine whether the particle will move when released.

Frictional force acting: F Max = u R = 0.7 x 5 x 9.81 x cos(30) F Max = 29.7N Weight acting down the slope: F = 5 x 9.81 x sin(30)F = 24.5N Frictional max is greater than the weight acting down the slope, th...
MI
Answered by Myles I. • Maths tutor
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Find values of x in the interval 0<x<360 degrees. For which 5sin^2(x) + 5 sin(x) +4 cos^2(x)=0

This question is split up into two parts. Firstly recall the trigonometric identities you know, the trick here is to eliminate one of the squared terms. Using 4sin^2(x) +4cos^2(x) = 4, the cos term is elimin...
JG
Answered by James G. • Maths tutor
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Differentiate the following... f(x)= 5x^4 +16x^2+ 4x + 5

The rule for differentiating a simple equation such as this is, to times the coefficient by the power and the take one away from the power. Therefore, lets look at 5x^4 you would times the 5 by 4 to get 20x^...
CM
Answered by Celia M. • Maths tutor
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y = 2ln(2x + 5) – 3x/2 , x > –2.5 find an equation to the normal of the curve when x = -2

2x + 5y = 11
SA
Answered by Shabeer A. • Maths tutor
5468 Views

Differentiate x^3+ x^2+2=y

This equals to dy/dx= 1/3 x 2 +1/3 x 1 This is because we divide by the power and then minus one from the powerSo it becomes x 3-1 /3 which can be simplified to 1/3 x 2 The 2 is differentiated to 0 because i...
VI
Answered by Vera I. • Maths tutor
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