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Differentiate y=x^3

dy/dx = 3x^2
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Answered by Rhiannon H. • Maths tutor
5511 Views

Find the integral between 1 and -2 for (4-x^2-3x^3)

= [4x - 1/3x 3 - 3/4x 4 ] 1 -2 = (4(1) - 1/3(1) 3 - 3/4(1) 4 ) - (4(-2) - 1/3(-2) 3 - 3/4(-2) 4 ) =(2 11/12) - (-8 + 8/3 - 12) =(2 11/12) - (-17 1/3) = 20 1 /4
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Answered by Alex G. • Maths tutor
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Integrate xcos(x) with respect to x

In order to do this question one has to first recognise that this is a product and thus has to be solved using Integration by parts. Firstly write out the formula: ∫u.dv/dx dx = uv - ∫v. du/dx dx (this is al...
DW
Answered by David W. • Maths tutor
5190 Views

2x + y = 12. P = xy^2. Show that P = 4x^3 - 48x^2 + 144x

We want to make P = xy^2 into something more complicated, which only has Xs, and no Ys. Firstly, you need to remember that when there are two equations, the question will almost definitely involve substituti...
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Answered by Jethro R. • Maths tutor
4193 Views

What does it mean for a function to have one to one mapping?

One to one mapping means is that there's only one value you could insert into the function that would give you a certain output. f(x) = 2x+1 is an example of one to one mapping where 3, for example, is the o...
JM
Answered by Joshua M. • Maths tutor
13327 Views