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Use Simpson's rule with 5 ordinates (4 strips) to find an approximation to "integral between 1 and 3 of" 1/sqrt(1+x^3) dx giving your answer to three significant figures.

Just as a note before I start, some of the symbols I use here will be horribly confused, this won't be an issue with a whiteboard but doing maths in a text editor is not great so I've had to make do. Taking ...
DA
Answered by Dominic A. • Maths tutor
10330 Views

Find the turning points and their nature of the graph y = x^3/3 - 7x^2/2 + 12x + 4

Answer = (3,17.5) maximum (4,17.33) minimum First differentiate y = x^3/3 - 7x^2/2 + 12x + 4 to find dy/dx. Now, at turning points dy/dx = 0 and factorise to find x when dy/dx = 0. Put x back into orginal eq...
JS
Answered by John S. • Maths tutor
9067 Views

Integrate (2x)(e^x)dx

Solve via Integration by parts: let u=2x and dv/dx=e x the function that is u and the one that is dv/dx is given by LATHE (easier to explain on whiteboard) make the table: u=2x => du/dx=2; dv/dx = e x =&g...
MR
Answered by Maksadul R. • Maths tutor
23149 Views

Intergrate 15x^2 + 7

Using the intergarting rules, you would add a power then divide that new number to the coefficent so you would get 5x^3 and just add one x to the 7 and dont forget the c. So the end answer would be 5x^3 + 7x...
WJ
Answered by William J. • Maths tutor
3937 Views

Given that log_{x} (7y+1) - log_{x} (2y) =1 x>4, 0<y<1 , express y in terms of x.

log_{x} (7y+1) - log{x} (2y) =1 --&gt; log_{x} [(7y+1)/2y]=1 (y =/= 0, Rules of logarithms i.e. difference of logarithms) --&gt; x = [(7y+1)/2y] (x&gt;0, Rules of logarithms i.e. log_{x} x = 1) --&gt; 2yx = ...
CL
Answered by Christopher L. • Maths tutor
6644 Views