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Given that y = sin(2x)(4x+1)^3, find dy/dx

The product rule states that (uv)' = u'v + uv' Therefore we know that to find dy/dx we must have (sin(2x))'(4x+1)^3 +sin(2x)((4x+1)^3)' We can differentiate sin(2x) to 2cos(2x) and using the chain rule we ca...
MM
Answered by Myles M. • Maths tutor
4926 Views

When do we use the quadratic formula, and when the completing the square method?

First, you have to understand that both are essentially the same; the formula is based on the completing the square method. ax^2+b^x+c=0 can with appropriate steps be transformed to x = (-b +- root(b^2-4ac))...
IP
Answered by Ioannis P. • Maths tutor
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Write down the values of (1) loga(a) and (2) loga(a^3) [(1) log base a, of a (2) log base a of (a^3)]

Let's first go to the whiteboard where I will explain what a logarithm is. The equation, loga(b) = x, could be re-written into the form, a^x = b. This is true for all logarithmic equations. There is a rule f...
SH
Answered by Sohail H. • Maths tutor
14592 Views

Find the stationary points of the curve given by the following function: f(x) = x^2 + 5x + 2

Differentiate the curve to get the gradient function: f'(x)= 2x + 5. Solve for x when f'(x) = 0 --> 2x + 5 = 0, 2x = -5, x = -5/2 Substitute into the original equation to find y: (-2.5)^2 + 5 * -2.5 + 2 =...
TD
Answered by Tutor49585 D. • Maths tutor
4796 Views

The curve C has equation x^2 + 2xy + 3y^2 = 4. Find dy/dx.

Here, we have to use implicit differentiation, along with the product rule. Remember that the product rule is (vu)' = vu'+uv'. Moving through the equation we have: x^2+2xy+3y^2 = 4 ==> 2x +2y + 2x*(dy/dx)...
CB
Answered by Chris B. • Maths tutor
13075 Views