Given that y = sin(2x)(4x+1)^3, find dy/dx

The product rule states that (uv)' = u'v + uv' Therefore we know that to find dy/dx we must have (sin(2x))'(4x+1)^3 +sin(2x)((4x+1)^3)' We can differentiate sin(2x) to 2cos(2x) and using the chain rule we can differentiate (4x+1)^3 to 12(4x+1)^2 Therefore our answer is 12sin(2x)(4x+1)^2 + 2cos(2x)(4x+1)^3

MM
Answered by Myles M. Maths tutor

4186 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

A curve C is mapped by the equation ( 1+x)(4-x). The curve intersects the x-axis at x = –1 and x = 4. A region R is bounded by C and the x-axis. Use calculus to find the exact area of R.


Find the general solution to the differential equation dy/dx = y/(x+1)(x+2)


How do you do algebraic long division?


How do I find the cartesian equation for a curve written in parametric form?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning