Given that y = sin(2x)(4x+1)^3, find dy/dx

The product rule states that (uv)' = u'v + uv' Therefore we know that to find dy/dx we must have (sin(2x))'(4x+1)^3 +sin(2x)((4x+1)^3)' We can differentiate sin(2x) to 2cos(2x) and using the chain rule we can differentiate (4x+1)^3 to 12(4x+1)^2 Therefore our answer is 12sin(2x)(4x+1)^2 + 2cos(2x)(4x+1)^3

MM
Answered by Myles M. Maths tutor

4090 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Differentiate 3x^2+1/x and find the x coordinate of the stationary point of the curve of y=3x^2+1/x


Differentiate y=3xe^{3x^2}+2x


How do I find the maximum/minimum of a curve?


The gradient of a curve is defined as Dy/dx = 3x^2 + 3x and it passes through the point (0,0), what is the equation of the curve


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences