Top answers

A ball is released from stationary at a great height. Explain how the forces acting on it change before it hits the ground and how these forces affect the velocity of the ball.

The initial velocity of the ball is 0, and so the only relevant force acting on it is weight pulling it downwards, so, the ball accelerates towards the ground. As the ball falls it hits air particles which c...
EC
Answered by Em C. • Physics tutor
9109 Views

What height do geostationary satellites orbit above the Earths surface?

You are given the following values: M e = 6x10 24 kgR e = 6.37x10 6 mA geostationary satellite appears to an observer on the ground to always be at the same position on the sky. This means its orbit must be ...
WM
Answered by Will M. • Physics tutor
11145 Views

How does the strong nuclear force between two nucleons varies with separation of the nucleons. Please detail the range over which the force acts.

The strong nuclear force is a fundamental force that binds quarks together to form nucleons. The force between nucleons is repulsive between similar nucleons (i.e. protons) before becoming attractive and bin...
CC
Answered by Claire C. • Physics tutor
3373 Views

find and symplify the following. Integrate ( 2x^5 - 1/(4x^3)- 5 )dx

first the second term can be split up to make integrating it easierits easier if the x 3 component is separatedthis eventually simplifies the second term to (-1/4) * x -3 so now the question is integrate (2x...
JL
Answered by Jacob L. • Physics tutor
2083 Views

a ball is dropped from rest off a cliff of height 50m, determine the final velocity of the ball assuming no air resistance.

Consider the appropriate equation of motion to solve this (use SUVAT method). The equation v^2=u^2+2 a s is appropriate to solve. Substituting in the knowns gives v=+sqrt(2 9.81 50)=31.32 which, quoted to th...
CJ
Answered by Cameron J. • Physics tutor
3129 Views