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a) A line passes through (0,9) and (3,12) write down the equation of this line . b) A line perpendicular to the line in part a passes through the point (3,14) write the equation of this line.)

a) The gradient of a line is given by the equation (change in y)/(change in x). Therefore to find the gradient of the line in part a we must do (12-9)/(3-0) = 1. Now we have the gradient we can use the formu...
RP
Answered by Rohil P. • Maths tutor
4502 Views

Simplify 125^(-2/3)

Simplify 125 -2/3 A negative indices means that we need to reciprocate the number or "flip it": 125 -2/3 = (1/125) 2/3 A fractional indices can be split up based on the denominator and numerator. H...
BH
Answered by Bethan H. • Maths tutor
6698 Views

I’m having some trouble understanding functions. Mainly concerning how to know what the input and outputs are. Could you give me an explanation?

The best way to think about a function is to see it as a machine. Your input is the item you put into the machine, the function is what the machine does, and then when you get out of the other side is your o...
CJ
Answered by Chelsie J. • Maths tutor
3791 Views

Find the value(s) of x which satisfies the equation 3x^2 + 6x + 3 = 0

First we must multiply the coefficient of x2 by the value with no x associated with it3x3 = 9Now we must find two numbers that add to make 6 and multiply to make 9+6x9 3 and 3Now we need to split the coeffic...
JG
Answered by Jacob G. • Maths tutor
3218 Views

The line L1 is given by the Equation y =3x+5, and the line L2 is given by the Equation 4y-12x+16=0. Show that the lines L1 and L2 are Parallel

Rewrite the equation for L2 to find an equation for y4y=12x-16; y = 3x - 4 2. The x-coefficient gives the gradient (or slope) of the line, so since the gradient of L1 is 3, and as we have just shown, the gra...
WS
Answered by William S. • Maths tutor
4976 Views