Find the value(s) of x which satisfies the equation 3x^2 + 6x + 3 = 0

First we must multiply the coefficient of x2 by the value with no x associated with it3x3 = 9Now we must find two numbers that add to make 6 and multiply to make 9+6x9 3 and 3Now we need to split the coefficient of the x value into these two numbers3x2 + 6x + 3 = 0Becomes:3x2 + 3x + 3x +3 = 0Now take a factor out of the first two terms and another out of the second two terms, leaving the same expression within the brackets.3x(x+1) + 3(x+1) = 0Now gather like terms into brackets(3x+3)(x+1) = 0If 3x+3 = 0 and x+1 = 0 then x can = -3/3 or -1 = -1Therefore x = -1

JG
Answered by Jacob G. Maths tutor

2543 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Please factorise fully: 2a^2 + 6a


Clare buys some shares for $50x. Later, she sells the shares for $(600 + 5x). She makes a profit of x% (a) Show that x^2 + 90x − 1200 = 0


Solve the simultaneous equation. 2x + y = 7 and 3x - y = 8


There are 11 pens in a box, 8 are black, 3 are red. Two pens are taken out at random without replacement. What is the probability the pens are the same colour?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences