Find the value(s) of x which satisfies the equation 3x^2 + 6x + 3 = 0
First we must multiply the coefficient of x2 by the value with no x associated with it3x3 = 9Now we must find two numbers that add to make 6 and multiply to make 9+6x9 3 and 3Now we need to split the coefficient of the x value into these two numbers3x2 + 6x + 3 = 0Becomes:3x2 + 3x + 3x +3 = 0Now take a factor out of the first two terms and another out of the second two terms, leaving the same expression within the brackets.3x(x+1) + 3(x+1) = 0Now gather like terms into brackets(3x+3)(x+1) = 0If 3x+3 = 0 and x+1 = 0 then x can = -3/3 or -1 = -1Therefore x = -1
JG
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