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If a rectangle has length (x-4), width (x-5) and area 12 then what is the value of x?

length x width = area (as rectangle) (x-4)(x-5)=12 x 2 -9x+20=12 x 2 -9x+8=0 (x-8)(x-1)=0 x=8 or x=1 <---- x can't be 1 as we would get negative length and width x=8
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Answered by Simon M. Maths tutor
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Factorise x^2+6x+8

Firstly, as it's highest term is x 2 , it must only have two factor brackets, so the answer has to look like (x + a) * (x + b).Then, to make 6x, we need the a and b term to be either 5 and 1, 4 and 2, or 3 a...
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Answered by Tom M. Maths tutor
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Show that the two lines are parallel: L1: 4y = 24x +12, L2: 2y + 13 = 12x

Two lines are parallel when they have the same gradient. When the equation is written in the form: y = mx + c, m is the gradient. We need to arrange our equations in the form y = mx + c as this is the easies...
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Answered by Dominique T. Maths tutor
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What is the product of prime factors of 270?

Firstly we need to make sure we understand the question and do this by defining the key elements: Prime number: A number that can only be divided by itself and 1 to give a whole number, i.e. 3, 7, 11 Factor:...
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Answered by Dominique T. Maths tutor
14195 Views

A right-angled triangle has a base of 5 cm, a height of 12 cm. Find the length of the hypotenuse.

Draw the triangle.Let the base = a, height = b and hypotenuse = ca = 5, b = 12, c = ?Using Pythagoras theorem, a 2 + b 2 = c 2 so, 5 2 + 12 2 = c 2 25 + 144 = c 2 169 = c 2 c = sqrt (169)c = 13So the hypoten...
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Answered by Abhiyan B. Maths tutor
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