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Solve the following pair of simultaneous equations 1)x+3y=11 2)3x+y=9

Rearrange equation 2 to make y the subject, then substitute the y expression into equation 1 and collect like terms: 3x+y=9 -->> y =9-3x x+3 y =11 -->> x+3(9-3x)=11 -->> x+27-9x=11 -->&g...
TD
Answered by Tutor94832 D. • Maths tutor
8053 Views

How to factorise x^2 + 6x +5

Firstly you check to see if there is a coefficient to the x 2 term, in this example there isn't so we know that both the brackets will have a single x in, (x + )(x + ). We also know both the signs in the bra...
FE
Answered by Fred E. • Maths tutor
40024 Views

Solve x^2+6x-7 by completing the square.

We know that to complete the square we put the equation in the form (ax+b)^2+c=0. So we must do that to our equation. We will begin by establishing what will be within our squared brackets. As there is no co...
JC
Answered by James C. • Maths tutor
10369 Views

Rearrange the following to make 'W' the subject: aw + 3 = 4(bw + 5)

aw + 3 = 4(bw + 5) Let's get rid of those brackets... aw + 3 = 4bw + 20 Now we rearrange... aw - 4bw = 17 Factorise... w(a - 4b) = 17 Final rearrange... w = 17 / (a - 4b) Done.
JM
Answered by Jack M. • Maths tutor
4433 Views

How do I draw a graph, y = mx + c, if I am only given m and a point that the line passes through?

Let's say we have the equation y = 2x + c and we are told that the line passes through the point (3, 4). Our first step is to use the numbers from the point (3, 4), by substituting them into our equation. Li...
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Answered by Alex D. • Maths tutor
3511 Views