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Solve the following simultaneous equations for x and y. 2x+5y=9 and 4x-3y=7

Here the best method to use will be elimination since using a substitution for x or y may produce some nasty fractions. The first thing to look for is that the 2x and 4x are nice multiples of each other. As ...
JG
Answered by Jamie G. • Maths tutor
8539 Views

How do you expand Double Brackets?

For this we will use the FOIL Method. This stands for Front, Outside, Inside, Last. This helps us to check that we have multipled everything. For example, lets use (x+1)(2x+3): Multiply the first terms: x 2x...
HR
Answered by Harry R. • Maths tutor
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(4x + 3)/(x + 1) + 2 = 8

(4x + 3)/(x + 1) + 2 = 8 Firstly minus the 2 from both sides (4x + 3)/(x + 1) = 6 Then multiply both sides by the denominator (x + 1) 4x + 3 = 6(x + 1) Expand the brackets. 4x + 3 = 6x + 6 Rearrange the equa...
JW
Answered by Jessica W. • Maths tutor
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Solve these pair of simultaneous questions: 3x+2y=17 4x-y=30

Let's solve for x first by substituting y in terms of x. 4x-y=30 y=4x-30 3x+2y=3x+2(4x-30)=3x+8x-60=11x-60 11x-60=17 11x=77 x=7 Now let's solve for y by substituting x for 7 3x +2y=17 3(7)+2y=17 21+2y=17 2y=...
JY
Answered by Jin-Ho Y. • Maths tutor
4732 Views

Solve the simultaneous equations. x^2 + y^2 = 29. y-x = 3

The 2 equations are: 1) x 2 + y 2 = 29 2) y-x=3 In this kind of simultaneous equation, you cannot take it away from each other. Instead, you need to substitue. To do so, rearrange the 2nd equation to make x ...
PS
Answered by Pallave S. • Maths tutor
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