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Starting with x^2+2x+1=0 use the method of factorising to solve for x.

x 2 +2x+1=0, (x+1)(x+1)=0, (x+1) 2 =0. So x=-1
RD
Answered by Rebecca D. • Maths tutor
4406 Views

Consider f:R -> R, f = x/ sqrt(x^2+1). Prove that for any a between -1 and 1, f(x)=a has only one solution.

f'(x)=( sqrt (x^2+1) - x * ( x / sqrt (x^2 +1) ) ) / (x^2+1) = (x^2 + 1 + x^2) / ( (x^2 + 1) * sqrt ( x^2 + 1) ) = 1 / ( (x^2 + 1) * sqrt (x^2 + 1) ). f'(x) > 0 for any x => f is increasing. When x-&gt...
AC
3484 Views

What is the point of intersection of two lines, and how would I find it?

The point of intersection is where the lines would cross if we drew them on the same graph, in your exam you may be asked to find the coordinates of this point. To do this we would first draw a sketch of the...
LS
Answered by Lisa S. • Maths tutor
4902 Views

factorise x^2+5x+6=0 and find x

x 2 +5x+6=0 (x+3)(x+2)=0 x=-3 and x=-2
AO
Answered by Ashley O. • Maths tutor
6129 Views

Solve 7x - 3 = 4x + 6

To solve the equation first collect all the unkown terms (letters) on one side and the known terms (numbers) on the other. Remember you must do the same to both sides to keep it balanced. First remove the 4x...
EH
Answered by Emily H. • Maths tutor
6773 Views