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Fully simplify (8a^2b * ab^4)/(2a^3b^2)

8a 3 b ab 4 2a 3 b 2 (can write this more clearly by hand using whiteboard) First go about seperating and collecting terms. Begin with the top line. 8 remains the same as there are no other known numbers. We...
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Answered by Archie I. Maths tutor
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Given that x(a+bx)(a-bx)=25x-4x^3, what is the value of b^(-a)? a,b>0

It's a two part question. First Part Expand the equation the left hand side to get a^(2)*x-b^(2)*x^3 thus comparing co-efficients a^2=25 and b^2=4 thus a= 5 b=2 Second Part Therefore b^(-a) is equal to 2^(-5...
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Answered by Cameron P. Maths tutor
10585 Views

Solve the inequality 7x+3y-4 > 5y-19x for y in terms of x.

7x+3y-4 > 5y-19x Adding 19x to both sides: 26x+3y-4 > 5y Subtracting 3y from both sides: 26x-4 > 2y Divide both sides by 2 to put the expression in its simplest form: 13x-2 > y or (remembering to...
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Answered by Danny L. Maths tutor
4296 Views

How do you solve quadratic inequalities?

Quadratic inequalities generally don't arrive in the standard quadratic form (Ax^2 + Bx +c) and so can be sometimes difficult to spot. However, if you see an X^2 - or brackets that expand to X^2 - on either ...
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Answered by David K. Maths tutor
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Factorise and solve x2 - 8x + 15 = 0

Factorise the quadratic into two brackets to make (x-3)(x-5)=0 Because the product of these brackets is zero then the value of one of the brackets must equal zero. In order for one of the brackets to have a ...
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Answered by Mohamed S. Maths tutor
9324 Views