Given that x(a+bx)(a-bx)=25x-4x^3, what is the value of b^(-a)? a,b>0

It's a two part question. First Part Expand the equation the left hand side to get a^(2)*x-b^(2)*x^3 thus comparing co-efficients a^2=25 and b^2=4 thus a= 5 b=2 Second Part Therefore b^(-a) is equal to 2^(-5) which is equal to (1/2)^5 which equals 1/32

CP
Answered by Cameron P. Maths tutor

8981 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

y is inversely proportional to d2 when d = 10, y = 4 d is directly proportional to x2 when x = 2, d = 24 Find a formula for y in terms of x. Give your answer in its simplest form.


I know the formula, but I don't understand it.


Write down the coordinates of the turning point of the graph y = x^2 – 8x + 25


work out 2/15 x 15/22


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences