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How do you find the maximum and minimum value of a quadratic function with no use of calculus?

By completing the square, since this makes you see that the square will always be >= 0 and the other part allows you to calculate the minima or maxima depending on the sign in front of x 2 . E.g. x 2 +4x=...
AO
Answered by Alexander O. • Maths tutor
10581 Views

Prove that 1/sin(2theta) - cos(2theta)/sin(2theta) = tan(theta)

Before we begin to approach this question, we first write down all the relevant formulae for this trigonometry question. We can see that we will need the double angle formulae (on account of the presence of ...
CM
Answered by Colin M. • Maths tutor
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Solve for y: 5(y – 2) + 2(y – 3) = 19

Most important thing is to do the same thing to both sides of the equation. 5(y – 2) + 2(y – 3) = 19 Step 1. Multiply out the brackets: 5y - 10 + 2y - 6 = 19 Step 2. Collect like terms & Simplify: 5y + 2...
RJ
Answered by Rahul J. • Maths tutor
11064 Views

Solve the following simultaneous equations: 3x + 2y = 16 2x + 3y = 14

Answer: x = 4, y = 2 Method: Eq 1) 3x + 2y = 16 Eq 2) 2x + 3y =14 Eq 1 x 2) 6x + 4y = 32 Eq 2 x 3) 6x + 9y = 42 New Eq 2 - New Eq 1) 5y = 10, so y = 2 Sub y into Eq 1) 3x + 4 = 16, 3x = 12, so x = 4
EO
Answered by Elizabeth O. • Maths tutor
8938 Views

Jorgen has 20 sweets in his pocket. The sweets are either blue or yellow. He picks a sweet and eats it and takes another sweet and eats it again. The probability of him picking two blue sweets is 6/30. How many yellow sweets does he have in his pocket.

1st step: Firstly we know 3 things: 1. There are 20 sweets in total 2. The sweets are either blue or yellow 3. The probability of picking two blue sweets in 6/30 We let the total number of blue sweets in his...
YS
Answered by Yusuf S. • Maths tutor
7141 Views