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Solve the simultaneous equations: 4x+y=25 and x-3y=16

Lets first give the equations names. 4x+y=25 (A) x-3y=16 (B) We want to get the equations so that they have either the same number of x's or same number of y's. So let's multiply equation (A) by three so tha...
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Answered by Michael D. • Maths tutor
10029 Views

The area of a rectangle is 8cm^2. It has a length of (3x+1)cm and a width of (2x+5)cm. Work out the value of x.

We know that the equation of the area of a rectangle is width times by length. Therefore: 8=(3x+1)(2x+5) If we multiply out the brackets we get: 8=(6x 2 +2x+15x+5), thus, 8=6x 2 +17x+5, and therefore, 0=6x 2...
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Answered by Oliver C. • Maths tutor
12923 Views

Finding the length of the side opposite a known angle while having the hypotenuse length known

Sin x is equal to the length of the opposite side divided by the length of the hypotenuse. So, the length of the opposite side is Sin x multiplied by the length of the hypotenuse
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Answered by Amer A. • Maths tutor
4271 Views

You area told that y is proportional to x2 and that when y = 75, x = 5. a) Find a formula for y in terms of x. b) Find the value of y when x = 3. c) Find the value of x when y = 1200.

a) when y=75 x=5 and y is proportional to x^2, so the answer is y=___x^2 if x=5, then x^2 = 25, and 75/25=3, so the answer is y=3x^2 b) if x=3, x^2=9, if you multiply this by 3, you get the answer of 27. c)i...
MB
Answered by Millie B. • Maths tutor
3781 Views

Solve the following simultaneous equations: x^2-y^2=9, x - y = 1

We first notice we have a linear and non linear equation. The simplest method to solve is to substitute the linear equation into the non linear equation and then solve for one of the unknowns. Then substitut...
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Answered by Shantu H. • Maths tutor
8947 Views