Make s the subject of the equation: 4st + 8 = 5r

To begin this question, we want to isolate the term containing the s, i.e. have the term containing the s by itself on one side of the equality. We do this by subtracting 8 from both sides. 4st = 5r - 8 To make s the subject of this equation, we want to undo whatever has been done to it. We notice that the s has been multiplied by 4 and by t, so, to counteract this, we divide both sides by 4 and t. s = (5r - 8) / 4t

SW
Answered by Sophie W. Maths tutor

3358 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Square ABCD has length (x+3)cm and area 10cm^2. Show x^2 + 6x = 1


how do you find the equation of a line perpendicular to another line at a point?


Solve this set of linear equation to find x and y: 1. 8x + 2y =48 2. 7x +3y =47


Express f(x) = x^2 + 5x + 9 in the form (x + a)^2 + b, stating the values of a and b.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning