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Solve the simultaneous equations: 5x + 3y = 41 and 2x + 3y = 20 Do not use trial and error.

5x + 3y = 41 2) 2x + 3y = 20 Subtract equation 2) from equation 1) to cancel the y's (3y-3y = 0) . Next we subtract the x's (5x - 2x = 3x) and then finally we have 41 - 20 = 21. We now have that 3x = 21 ( re...
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Answered by David T. • Maths tutor
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Solve the equation "x^2 + 3x - 4 = 0".

Recognise that quadratic can be factorised: (x+4)(x-1)=0 This gives the solutions x=-4 and x=1 by inspection.
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Answered by Zak K. • Maths tutor
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3x² = 75 Find the value of x.

First Simplify the numbers we know. Therefore we get: x 2 =75/3 which is the same as x 2 =25 Now find the square root of 25, which is 5 or -5. Therefore x=5 or -5
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Answered by Daniel B. • Maths tutor
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How do you expand brackets in a quadratic equation?

To expand the brackets in a quadtratic equation you should multiply whatever is outside the bracket by that which is inside the bracket. For example: 2(x+3) First multiply the first part of the bracket with ...
DH
Answered by Dorothy H. • Maths tutor
5622 Views

Express the recurring decimal 0.2131313 as a fraction

Firstly, identify the recurring portion of the decimal. In this case, it is "13" set up an equation "x=0.2131313 You need to place the repeating section to the left of the decimal point. To do...
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Answered by Abhijit N. • Maths tutor
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