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Explain the use of the quadratic formula to solve quadratic equations.

To explain this to a student, I would start by explaining the general formula for a quadratic equation, (ax^2 + bx + c = 0). Then I would show using an example, how the a,b and c can be substituted with numb...
TN
Answered by Tom N. • Maths tutor
3390 Views

How would you work out the length of an hypotenuse, if the length of the opposite side is 3 cm and the length of the opposite side is 4 cm?

You would use Pythagoras theorem, which states, a^2 + b^2 = c^2. Where a is the opposite side to the angle, b is the side adjacent to the angle and c is the hypotenuse. So if a = 3 cm, and b = 4 cm, c^2 woul...
OA
Answered by Othniel A. • Maths tutor
4744 Views

Solve the simultaneous equations: 2x+2y=12 x-y=8 You must show your working

The first thing we want to do is change the first equation so it's either all x's or all y's, we don't want a mixture. Now looking at the bottom equation, we can rearrange it by adding y to both sides. This ...
KA
Answered by Kasim A. • Maths tutor
6012 Views

How do I rearrange this equation for x? y=(x+2)/(3x-1) +2

First of all we must consider the fraction. To eliminate this we multiply both sides through by 3x-1. We then end up with y(3x-1)=(x+2)+2(3x-1). The next step is to expand out the brackets and collate terms,...
CM
Answered by Charlie M. • Maths tutor
4997 Views

Show (4+5/7) - (2+1/3) as a single mixed fraction.

Mixed number -> top heavy fraction: 4 + 5/7 = ((4 7)+5)/7 = (28+5)/7 = 33/7 2+ 1/3 = ((2 3)+1)/3 = (6+1)/3 = 7/3 Common denominator by multiplying by each others: 33/7 = (33 3)/(7 3) = 99/21 7/3 = (7 7)/(...
ER
Answered by Ethan R. • Maths tutor
4200 Views