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Find the coordinates where the curve y=x^2+6x+5 crosses the x-axis.

When any curve crosses the x-axis, the y-coordinate is 0 at that point. Hence, our answers will have y=0. So we want to solve x^2+6x+5=0. From before, we have that x^2+6x+5=0 can be rewritten as (x+5)(x+1)=0...
JI
Answered by Jonny I. Maths tutor
5171 Views

Factorise fully x^2+6x+5=0

To start, notice that we have x^2 in our equation. This means that our answer is of the form (x )(x ). We now look for integers that give 5 when multiplied together. The only way we can do this is with the n...
JI
Answered by Jonny I. Maths tutor
5986 Views

There are 10 balls in a bag. The balls are the same apart from their colour. Of the 10 balls, 3 are black, 5 white, 2 red. What is the probability of picking a white ball from the bag.

To calculate the probability assume it is equally likely to choose any of the 10 balls. This is reasonable as we are told that the balls are the same apart from their colours. If we label each ball by number...
AS
Answered by Alvin S. Maths tutor
8337 Views

Solve the following for X and Y: 2y+4x=14 and x-y=-1

Firstly, Take equation 1 (2y+4x=14) and divide it all by 2. This gives y+2x=7. Next make Y the 'subject' AKA put it on it's own. To do this Subtract 2x from both sides. Now we have Y=7-2X. Here you can see Y...
TM
Answered by Toby M. Maths tutor
5359 Views

Expand and simplify (5a-2b)(3a-4b)

=(5a x 3a) + (5a x -4b) + (3a x -2b) + (-2b x -4b) =15a^2 - 20ab - 6ab + 8b^2 =15a^2 - 26ab + 8b^2
PI
Answered by Paul I. Maths tutor
11030 Views