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Solve the simultaneous equations: x^2 + y^2 = 29 and y - x = 3

To solve these equations we need to eliminate one of the variables, so make y the subject of the second equation: y = x + 3. Now y can be substituted into the first equation: x^2 + (x+3)^2 = 29. Expanding (x...
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Answered by Trisha G. • Maths tutor
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Solve 3(x-2) = 21

To begin, understanding the basica concept of algebra and multiplication using brackets needs to be covered as I have met quite a few children who have been used to these equations but are still unsure about...
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Answered by Nicole F. • Maths tutor
4162 Views

Expand and simplify (6x - 2y)(3x - 7y)

Expand brackets: 18x^2 - 42xy - 6xy + 14y^2 Simplify: 18x^2 - 48xy + 14y^2 3 marks
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Answered by Beth W. • Maths tutor
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Factorise and solve x^2 - 8x + 15 = 0.

The easiest method to solve quadratic equations by hand is by factorisation - which means putting the equation into brackets, effectively expressing the equation as a product of two linear expressions. Imagi...
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Answered by Rachel B. • Maths tutor
4759 Views

John and simon share £80 in the ratio 5:3 in that order, how much do they each receive?

5+3=8 80/8= 10 therefore one part = 10 john receives 5 parts, simon receives 3 john=5x10=50 simon=3x10=30
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Answered by Monty C. • Maths tutor
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