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How do I find the roots and and coordinates of the vertex of the graph y = 2x^2 + 4x - 8 ?

y = 2x^2 + 4x - 8y = 2( x^2 + 2x - 4)Completing the square:y = 2( (x+1)^2 - 1 - 4 )y = 2(x+1)^2 -10the vertex of graph lies at the minimum value of y, and this occurs when x = -1:y = 2(-1+1)^2 -10y = -10ther...
JA
Answered by Joe A. • Maths tutor
7866 Views

s^2 - 2s - 24 = 0

s 2 ​ - 18s = 0(s + 4)(s - 6) = 0s = -4 s = 6
NP
Answered by Natasha P. • Maths tutor
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Prove that (2n+3)^2-(2n-3)^2 is a multiple of 8 for positive integer values of n

To prove that (2n+3) 2 -(2n-3) 2 is a multiple of 8 we are going to deal with the first bracket and then the second bracket. When a bracket has 2 next to it, this means that you multiplying the bracket, by t...
SD
Answered by Sioned D. • Maths tutor
25215 Views

Solve the simultaneous equations: 2x-3y = 24 and 6x+2y = -5

There are numerous alternative ways to solve these simultaneous equations. For this problem, one of the simplest methods is to multiply the first equation by 3, so that we get 6x in both equations: (2x - 3y)...
AS
Answered by Augustinas S. • Maths tutor
4729 Views

Rearranging formulae

Rearrange 1/u + 1/v = 1/f to make u the subject of the formula. Give your answer in its simplest form. There are a number of ways to approach this problem. By subtracting 1/v on both sides we get 1/u as the ...
RS
Answered by Robert S. • Maths tutor
13877 Views