Solve the simultaneous equations: 2x-3y = 24 and 6x+2y = -5

There are numerous alternative ways to solve these simultaneous equations. For this problem, one of the simplest methods is to multiply the first equation by 3, so that we get 6x in both equations:

(2x - 3y)3 = 243, giving 6x - 9y = 72

If we now subtract the second equation from the first one (multiplied by 3), we get:

(6x - 9y) - (6x + 2y) = 72-(-5)

This way we are left only with y on the left hand side:

-9y - 2y = 77

-11y = 77

Thus we found the value of y:

y = -77/11 = -7

Now we can substitute the value for y into the first equation and find x (substituting into the 2nd equation would also work fine):

2x - 3(-7) = 24

2x + 21 = 24

2x = 3

x = 3/2

Therefore, the solution is: x = 3/2 and y= -7

AS
Answered by Augustinas S. Maths tutor

4092 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

A 4 digit number is picked. It's second digit is a prime number, it must be even and it must be greater than 5000. How many possible numbers can be picked?


The first 4 terms of a different sequence are: 9, 13, 17, 21. Find an expression for the nth term of the sequence.


How do I go about adding, subtracting, multiplying and dividing fractions?


Solve x^2-6x+8=0


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning