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Find the inverse of y = 2x+1/ x-1

the aim of finsing the inverse is making x the subject. To start we need to multiply both sides by: (x-1), giving us:y(x-1) = 2x+1now we need to expand the brackets:yx - y = 2x+1now gather all the x componen...
AS
Answered by Amelia S. Maths tutor
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Whats the inverse of y = 2x+1/x-1 ?

To find the inverse we're wanting to make x the subject. First start by multiplying both sides by (x-1), this gives us y(x-1) = 2x+1. Expand the brackets giving yx - y = 2x+1. Gather all the x components ont...
AS
Answered by Amelia S. Maths tutor
19974 Views

Solve (x + 2)(x+3) = (2x+4)

Expand: x 2 + 2x + 3x +6 = 2x+4 Take (2x+4) from both sides: x 2 +3x+2 = 0 Facorise: (x+2)(x+1) = 0 So solutions are x=-2 and x=-1
MT
Answered by Michael T. Maths tutor
8482 Views

Find the solutions of the equation x^2 - 2x - 8 =0

First factorise the equation into 2 sets of brackets: You can do this by looking at the constant in the quadratic, 8. Try and find 2 numbers that multiply together to make 8 (such as 4 and 2), and that can b...
TV
Answered by Tom V. Maths tutor
8634 Views

Solve the equation (2x+3)/(x-4)-(2x-8)/(2x+1)=1 and give the answer to 2 decimal places

To start off with we need to remove the two denominators (the bottom part of the fractions) on the left hand side of the equation. This can be achieved by multiplying the through the whole equation by (x-4)(...
JJ
Answered by Jake J. Maths tutor
10025 Views