Whats the inverse of y = 2x+1/x-1 ?
To find the inverse we're wanting to make x the subject. First start by multiplying both sides by (x-1), this gives us y(x-1) = 2x+1. Expand the brackets giving yx - y = 2x+1. Gather all the x components onto the same side:yx - 2x = 1+ynow factorise the left hand side:x(y-2) = 1+yand make x the subject|:x = 1+y/y-2therefore the solution of the inverse isf(x)^-1 = 1+x/ x-2
AS
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