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Solve the following equation: 13y - 5 = 9y + 27

13y - 5 = 9y + 2713y - 9y = 27 + 54y = 32y = 32/4 y = 8
MG
Answered by Megan G. • Maths tutor
3914 Views

Solve the simultaneous equations x^2 + y^2 =13 and x= y - 5.

(y-5) 2 + y 2 = 13y 2 -10y +25 + y 2 =13.2y 2 -10y+12=0.y 2 -5y+6=0.(y-3)(y-2)=0. So, y=3 or y=2. Then substituting these values of y back into x=y-5 gives, x=-2 when y=3 and x=-3 when y=2.
HD
Answered by Hollie D. • Maths tutor
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Expand (x+4)(x-4)=33 to give values of x

Use FOIL to expand the brackets. To do this, we start by multiplying the FIRST value in each bracket which in this case is x so we get x^2. Then we multiply the OUTSIDE two values, so here that is x and -4 s...
AB
Answered by Aria B. • Maths tutor
4027 Views

How do surds relate to powers and roots?

To understand surds we have to understand powers and there uses. So to start we should look at powers such as what is 2 2 , 3 2 , and 5 2 . This shows us going up but then we look at how we square root thing...
AG
Answered by Alistair G. • Maths tutor
3560 Views

Solve n^2 – n – 90 = 0 to find value of n

Firstly you want to factorise this expression. You have n 2 , so you know you want to multiple n by itself. Next, you want to think carefully about what two numbers add to get -1 (the coefficient of the seco...
AI
Answered by Ahmed I. • Maths tutor
4934 Views