Solve n^2 – n – 90 = 0 to find value of n

Firstly you want to factorise this expression. You have n2, so you know you want to multiple n by itself. Next, you want to think carefully about what two numbers add to get -1 (the coefficient of the second value of the expression, -n) and multiply to get -90. You have two negatives so you know one of your numbers is going to be negative and the other positive (if they were both negative you'd get +90, same if they were both positive). You'll figure out the two numbers you're looking for are - 10 and + 9 ( - 10 + 9 = -1, - 10 x 9 = - 90). So now you have(n + 9)(n - 10) = 0 For this to be true, one of the expressions on the left have to equal 0, so either n + 9 = 0 or n - 10 = 0. The possible values are therefore n = 10 or n = - 9, final answer

AI
Answered by Ahmed I. Maths tutor

3837 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

2 chocolates weight 250g, there are 220 calories in 100g of chocolate. How many calories are in one chocolate?


How do I solve the quadratic equation x^2+4x+3=0


How to I factorise a quadratic equation?


solve (y+1)^2 = 4


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning