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Please expand the following brackets: (x+3)(x+5). Give your answer in its simplest form.

So how I would start to solve this problem is by using a method called the claw method (because it looks like a claw).So in order to expand the brackets, we need to multiply each term in the first bracket by...
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Answered by Clarence L. • Maths tutor
4759 Views

How do you solve an equation like: 5/(x+2) + 3/(x-3) = 2?

Multiply every term by a denominator to eliminate it;5 + 3(x+2)/(x-3) = 2(x+2)5 + 3x+6/(x-3) = 2x+45(x-3) + 3x+6= (2x+4)(x-3)2) simplify5x-15+3x+6=2x 2 -12+4x-6x8x-9=2x 2 -12-2x2x 2 -10x-3=03) use the equati...
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Answered by Tom H. • Maths tutor
6608 Views

Solve the simultaneous equations: x + 2y = 13, 4x - 3y = 8.

Multiply both sides of the equation x + 2y = 13 by 4 to get 4x + 8y = 52. Subtract 4x - 3y = 8 from 4x + 8y = 52 to get 11y = 44. Divide both sides of 11y = 44 by 11 to get y = 4. Since we now know y = 4, we...
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Answered by Kate P. • Maths tutor
6176 Views

Solve the simultaneous equations y = x^2 +3x and y = x+8

Because both of the equations are equal to y, the first thing we do is make them equal to each other:x^2 + 3x= x + 8We then want to rearrange the equation so that everything is on the same side of the equals...
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Answered by Jessica W. • Maths tutor
4650 Views

solve the simultaneous equations: 3x + 5y = 4 ; 7x - 3y = 8

first recognise that if you double the first equation the both equations will be equal to 8.so now we have 6x + 10y = 8 ; 7x - 3y = 8now we can set the equations equal to each other to get 6x + 10y = 7x - 3y...
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Answered by Elizabeth W. • Maths tutor
4485 Views