solve the simultaneous equations: 3x + 5y = 4 ; 7x - 3y = 8

first recognise that if you double the first equation the both equations will be equal to 8.so now we have 6x + 10y = 8 ; 7x - 3y = 8now we can set the equations equal to each other to get 6x + 10y = 7x - 3yby rearranging for x we get:x = 13ynow substituting this into the first orignal equation we get:3(13y) + 5y = 4 so,39y + 5y = 4 so,44y = 4 so,y= 1/11then substtuting this value into x = 13y we get x = 13/11 ; y=1/11

EW
Answered by Elizabeth W. Maths tutor

3742 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Can you explain when we flip the inequality direction when solving inequalities.


Write √5 ( √8 + √18 ) in the form a√10, where a is an integer, without using a calculator.


Solve the simultaneous equations; 3x+2y=11 and 2x-2y=14


How do I draw a straight line graph given a y=mx+c equation by the table method?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences