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A straight line passes through the point (0, 6) and is perpendicular to y = 4x - 5. Find the equation of this line, giving your answer in the form y = mx + c .

perpendicular so the gradient is -1/4 y= -1/4x +CSub in the coordinate (0,6) 6 = -1/4 (0) +C C=6y=-1/4x +6
MS
Answered by Maria S. • Maths tutor
8589 Views

factorise x^2 - 8x -65

Two numbers add/ subtract to make -8Two numbers multiply to make -65. These are 1 and 65 as well as 5 and 13Seeing as 1 and 65 cant add or subtract to make -8 the numbers we'll use are 5 and 13. These also s...
KC
Answered by Kavi C. • Maths tutor
5437 Views

Find the positive solution to the equation (x^2+9x+18)/(x^2-9)=10

If we first factorise the top and the bottom of the equation we can see that the top is equal to (x+6)(x+3) and the bottom is (x-3)(x+3). This means we can divide the top and bottom by (x+3) giving us a resu...
JR
Answered by Joseph R. • Maths tutor
3438 Views

(e*sqrt(e))/cuberoot(e^2)=e^k find k

This an indices question. What you need to do is simplify the left hand side so that you have e to some power and that will give you k. You can start with the rule that square roots and cube roots are 1/the ...
TD
Answered by Tamanna D. • Maths tutor
3503 Views

Find the points where the curve given by: y = x^2 - 4x -12, and the line given by y = 2x - 12

They intersect at (0, -12) and (6, 0)
RV
Answered by Rufus V. • Maths tutor
3038 Views