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Solve the quadratic equation, x^2 - 4x -5 = 0

Solve x 2 - 4x - 5 = 0 A very full explanation would be: Start by listing the pairs of numbers that can be multiplied together to get 1 * -5 = -5 (i.e. the coefficient of the first term multiplied by the las...
RH
Answered by Ryan H. • Maths tutor
5773 Views

Solve for y and x, where x=y+1 and y=2x+3

Simultaneous equations: x=y+1 y=2x+3 First solve for x. y=2x+3 so first equation becomes: x=(2x+3)+1 x-2x-3-1=0 -1x-4=0x+4=0 x=-4 Solve for y: y=2x+3 y=2(-4)+3 y=-8+3y=-5
TS
Answered by Tom S. • Maths tutor
4344 Views

Solve the simultaneous equations 2x + y = 7 and 3x - y = 8

There are three methods for solving simultaneous equations: elimination, substitution and by using graphs.Elimination is a good method in this case as the y terms are equal in both equations. We just add the...
TJ
Answered by Tia J. • Maths tutor
7794 Views

How do you solve the simultaneous equations x^2+y=1 and -x+y=-1

First rearrange the second equation so that it's equal to y. You do this by adding x and y to both sides of the equation. You should then have y=x-1. Next you should sub y=x-1 into the first equation, x 2 +y...
CM
Answered by Chloe M. • Maths tutor
3507 Views

Make x the subject of, 4(x+1)/(x+2) = y

The fundamental rule to keep in the back of your head is 'whatever happens to one side must happen to the other'. This way we can be sure that whatever is on the left hand side of the equals sign will be the...
JW
Answered by Jack W. • Maths tutor
5057 Views