How do you solve the simultaneous equations x^2+y=1 and -x+y=-1

First rearrange the second equation so that it's equal to y. You do this by adding x and y to both sides of the equation. You should then have y=x-1. Next you should sub y=x-1 into the first equation, x2+y=1. You should now be left with x2+x-1=1. This can be rearranged by subtracting 1 from each side to create the quadratic equation x2+x-2=0. This can be solved in which ever way you prefer; I would factorise it, leaving you with (x+2)(x-1)=0. Therefore x=-2 or x=1

CM
Answered by Chloe M. Maths tutor

3177 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Find the volume of a right angled triangular prism with an angle of 28 degrees, hypotenuse of length 10 cm, and projected length of 12.5 cm. Give your answer in cm^3, to three significant figures.


Express x^2+4x-12 in the form (x+a)^2 +b by completing the square.


Solve 5x-2=3x+11


An isosceles triangle has a base with length x+4 and the other two sides have length x+3. The perimeter of this isosceles triangle is 16cm. Find the area of the triangle.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning