How do you solve the simultaneous equations x^2+y=1 and -x+y=-1

First rearrange the second equation so that it's equal to y. You do this by adding x and y to both sides of the equation. You should then have y=x-1. Next you should sub y=x-1 into the first equation, x2+y=1. You should now be left with x2+x-1=1. This can be rearranged by subtracting 1 from each side to create the quadratic equation x2+x-2=0. This can be solved in which ever way you prefer; I would factorise it, leaving you with (x+2)(x-1)=0. Therefore x=-2 or x=1

CM
Answered by Chloe M. Maths tutor

2909 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Harry drives from Exeter to London in 4 hours at an average speed of 70km/h. Ron drives from Exeter to London in 5 hours. (a) Assuming Ron took the same route as Harry, calculate Ron's average speed.


solve the simultaneous equations 3x+7y=18 and 7x+9y=8


Why do you times the reciprocal of the second fraction by the first when dividing fractions.


A is the point with coordinates (5, 9) B is the point with coordinates (d, 15) The gradient of the line AB is 3 Work out the value of d.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning