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Multiply out: (x - 2)(x + 5)

This can be seen as the same as (x)(x + 5) + (-2)(x + 5). So you are just multiplying the first value in the first brackets with both the values in the second brackets. This is x x + x 5 which equals x^2 + 5...
TS
Answered by Thomas S. • Maths tutor
6462 Views

How do you solve a simultaneous equation such as x+2y=10 and 3x+2y=18?

To solve simulatenous equations there are two main methods, substitution and elimintion. The first method requires the principle where if x is equal to a number, say x=2 then we can substitute this in, for e...
KR
Answered by Katie R. • Maths tutor
5533 Views

make y the subject of this expression p = ((x+y)/5)^1/2

To maintain the equality everything that is done to one side needs to be done also to the other. First, we square both sides to get rid of the power on the right-hand side. What we get is p^2 = (x+y)/5. Now ...
GS
Answered by Giorgia S. • Maths tutor
3098 Views

Solve 4 + 3(2x - 5) = x + 9.

4 + 3(2x - 5) = x + 9, 3(2x - 5) = x + 5, 6x - 15 = x + 5, 5x = 20, x = 20/5, x = 4
MC
Answered by Megan C. • Maths tutor
7135 Views

Simultaneous questions: 2x+y=7, 3x-y=8

First of all, you want to get both of the questions equating to y as this is a common factor between the two equations. SO y=7-2x and 3x-8=y As both of the equations are equal to y, we can set them equal to ...
BJ
Answered by Bronnie J. • Maths tutor
3410 Views