Simultaneous questions: 2x+y=7, 3x-y=8

First of all, you want to get both of the questions equating to y as this is a common factor between the two equations. SO y=7-2x and 3x-8=y As both of the equations are equal to y, we can set them equal to each other. SO 7-2x=3x-8 Now you want to bring all of the common factors together. So x's on one side, integers on the other. 7+8=3x+2x 15=5x We now want to divide both sides by 5 so we know what once x is equal to. 3=x We now fill this back into an equation to find out y 2(3) + y =7 6+y=7 y=7-6 y=1 Therefore, x=3, y=1

BJ
Answered by Bronnie J. Maths tutor

2933 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

root3 (root6 + root12) can be written as Aroot2 + B


Solve for x 2x +3 + (4x-1)/2 = 10


Find the equation of the line that passes through (2, 4) and (7, -11)


A ladder (length 314 cm) is leaning up against a wall. The length between the ladder and the wall is 1.54 m. At what angle is the ladder leaning up against the wall? Round your answer to 2 d.p.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning