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How do you find the turning point of a quadratic equation?

We factorise the equation by completing the square.Take y=x 2 + ax + bWhen we complete the square we have y= (x+1/2a) 2 -a 2 +b which is y= (x+1/2a) 2 + c where c = -a 2 +bThe turning point would be at (-1/2...
WF
Answered by Wiktoria F. • Maths tutor
41042 Views

How do I approach simultaneous equations with 2 unknowns?

The two common ways to approach them is either by substitution or addition/subtraction. Firstly, for substitution, rearrange one of your equation so that one of the unknowns becomes the subject and then subs...
LS
Answered by Louis S. • Maths tutor
3017 Views

Solve the simultaneous equations 2x + 3y = 19 , 3x + y = 11

Rearrange to make the y component the subject3y = 19 - 2x , y = 11 - 3xMultiply the second equation by 33y = 33 - 9xEquate to each other19 - 2x = 33 - 9xRearrange7x = 14Divide by 7x = 2Substitute x=2 into on...
DB
Answered by David B. • Maths tutor
4807 Views

Write x^2 + 4x + 18 in the form (x + a)^2 + b, where a and b are constants to be determined.

(x + 2)^2 + 14. a = 2, b = 14
DH
Answered by Danqing H. • Maths tutor
4294 Views

The functions f and g are such that f(x)=5x+2 and g(x)=-x-4. a) Find fg(x). b) Find ff(x). c) Solve fg(x) = ff(x).

a) fg(X) = 5(-x-4)+2 = -5x-20+2 = -5x-18b) ff(X) = 5(5x+2)+2 = 25x+10+2 =25x+12c) 25x+12=-5x-18 25x+5x=-18-12 30x=-30 x=-1
MA
Answered by Maria A. • Maths tutor
5212 Views