Solve the simultaneous equations 2x + 3y = 19 , 3x + y = 11
Rearrange to make the y component the subject3y = 19 - 2x , y = 11 - 3xMultiply the second equation by 33y = 33 - 9xEquate to each other19 - 2x = 33 - 9xRearrange7x = 14Divide by 7x = 2Substitute x=2 into one of the equations and solve for yy = 11 - (3 x 2) = 5
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Related Maths GCSE answers
All answers ▸Square ABCD has length (x+3)cm and area 10cm^2. Show x^2 + 6x = 1
Solve for x: 2x^2 + 7x + 6 = 0
a) You area told that y is proportional to x2 and that when y = 75, x = 5. Find a formula for y in terms of x. y = x b) Find the value of y when x = 3. c) Find the value of x when y = 1200.
f(x) = 3x - 2a || g(x) = 2ax + 1 || fg(x) = 2x + b/2