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Expand (x+2)(x-3)(x+4)^2

(x+2)(x-3)(x+4)^2 = (x^2 - x - 6)(x^2 + 8x + 16) = (x^4 + 8x^3 +16x^2 - x^3 - 8x^2 -16x - 6x^2 - 48x - 96) = x^4 +7x^3 + 2x^2 - 64x - 96)
RG
Answered by Roisin G. • Maths tutor
3471 Views

2^6*2^10=?

When multiplying two same numbers with powers, we add the powers together. The answer of this question would be 2^16, which is also 65536.
HH
Answered by Hamza H. • Maths tutor
3489 Views

Show that 12 cos 30° - 2 tan 60° can be written in the form root (k) where k is an integer.

To answer these questions, students must know the values of cos30 and tan60. If you don't know them off by heart, you can work them out using an equilateral triangle. cos 30° = adj / hyp = root(3) / 2 tan 60...
MA
Answered by Marco A. • Maths tutor
5107 Views

Using the quadratics formula find the two solutions to x^2 + 3x + 2 = 0.

x 1 = (-b + (b 2 - 4ac) 1/2 )/2a and x 2 = (-b - (b 2 - 4ac) 1/2 )/2a. So with the values a = 1, b = 3 and c = 2: x 1 = (-3 + (3 2 - 8) 1/2 )/2 and x 2 = (-3 - (3 2 - 8) 1/2 )/2, x 1 = (-3 + 1)/2 = -1 and x ...
RD
Answered by Rebecca D. • Maths tutor
4165 Views

Starting with x^2+2x+1=0 use the method of factorising to solve for x.

x 2 +2x+1=0, (x+1)(x+1)=0, (x+1) 2 =0. So x=-1
RD
Answered by Rebecca D. • Maths tutor
4476 Views