Using the quadratics formula find the two solutions to x^2 + 3x + 2 = 0.
x1 = (-b + (b2 - 4ac)1/2)/2a and x2 = (-b - (b2 - 4ac)1/2)/2a. So with the values a = 1, b = 3 and c = 2: x1 = (-3 + (32 - 8)1/2)/2 and x2 = (-3 - (32 - 8)1/2)/2, x1 = (-3 + 1)/2 = -1 and x2 = (-3 - 1)/2 = -2.
RD
Related Maths GCSE answers
All answers ▸Expand and simplify (x+1)(2x+3).
Solve by completing the square: x^2 - 8x + 12 = 0
X is a prime number higher than the square of 5 and lower than the square of 7. What are the smallest and largest possible values for X?
a) Find the equation of the line that passes through (2,10) and (4,16) b) Find the point where the line in (a) intersects the line y=5x-2