Top answers

2.4 g of magnesium reacts with 1.6 g of oxygen. What is the empirical formula of the oxide formed?

Ar of Magnesium = 24; Ar of Oxygen = 16 number of moles = mass divided by Ar number of moles of Mg = 2.4/24 = 0.1 number of moles of Oxgen = 1.6/16 = 0.1 ratio of Mg to O = 0.1:0.1 = 1:1 So oxide produced is...
KT
Answered by Katrina T. • Chemistry tutor
18351 Views

Can you explain what stoichometry actually is and why the ratio is not the same as the number of moles?

Stoichiometry is just a way of relating two species that react, in a ratio. EXAMPLE: 1A + 2B -> 3C Now usually this would be written as A + 2B -> 3C but I've written the 1 to exaggerate the point. Now ...
MR
Answered by Michael R. • Chemistry tutor
6537 Views

What mass of CO2 will be produced when 50 g of CaCO3 decomposes?

CaCO 3 decomposition: CaCO 3 -> CaO + CO 2 The first thing to do here is to calculate the relative formula mass of CaCO 3 and CO 2 . RFM of CaCO 3 = 40 g + 12 g + (16 g x 3) = 100 g RFM of CO 2 = 12 g + (...
JH
Answered by Joshua H. • Chemistry tutor
99098 Views

The relative formula mass of CaO is 56 and the relative formula mass of CO2 is 44. What is the mass of CaO that can be obtained from 200 g of CaCO3. CaO3 -> CaO + CO2

We are given the relative formula mass (RFM) of CaO and CO 2 , we should therefore calculate the RFM of CaO 3 : RFM of CaCO 3 = 40 + 12 + (16 x 3) = 100 If we look at the reaction in the question, we can see...
JH
Answered by Joshua H. • Chemistry tutor
32123 Views

What is the relative formula mass of CaCO3?

The relative formula mass (RFM) is simply just a sum of the atomic masses that make up the compound in question. Ca = 40 C = 12 O = 16 RFM of CaCO 3 = 40 + 12 + (16 x 3) = 100 Note we have three oxygens so w...
JH
Answered by Joshua H. • Chemistry tutor
72882 Views